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... 1 Ecological Systems Analysis Spring 2012 mandatory exercise I page 1 Ecological Systems Analysis ... do not hand in computer prints of the same solution for several people. Exercise 1 (Environmental ... 1 ... 1 Ecological Systems Analysis Spring 2012 mandatory exercise I page 1 Ecological Systems Analysis ... 1 ...

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... Materials, Polymer Chemistry, ETH Zürich Short fiber composites ‰ Polymers have a stiffness of 1- 3 GPa ... , p2, p3) ‰ System with N fibers – 2nd order orientation tensor – 4th & 6th order tensors 1 φ θ p 2 3 ... Materials, Polymer Chemistry, ETH Zürich Short fiber composites ‰ Polymers have a stiffness of 1- 3 GPa ... , p2, p3) ‰ System with N fibers – 2nd order orientation tensor – 4th & 6th order tensors 1 φ θ p 2 3 ... Slide 1 ...

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... Slide 1 10/5/2015 1 1 Lecture # 3 – Fall 2015 1 D. Mohr 151-0735: Dynamic behavior of materials and ... Lecture # 3 – Fall 2015 7 D. Mohr 151-0735: Dynamic behavior of materials and structures -2 - 1 0 1 2 -2 - 1 ... Slide 1 10/5/2015 1 1 Lecture # 3 – Fall 2015 1 D. Mohr 151-0735: Dynamic behavior of materials and ... Lecture # 3 – Fall 2015 7 D. Mohr 151-0735: Dynamic behavior of materials and structures -2 - 1 0 1 2 -2 - 1 ... Slide 1 ...

Diapositiva 1

... -TONES MODULATION RESULTS 0 1 2 3 4 15 N 14 N 16 O (10 0 0- 00 0 0) P(35) S = 1.66*10 -22 cm 14 N 2 18 O ... (10 0 0- 00 0 0) P(9) S = 2.43*10 -22 cm 14 N 2 16 O (11 1 0-01 1 0) P(56) S = 7.46*10 -23 cm T = 81.2 ... -TONES MODULATION RESULTS 0 1 2 3 4 15 N 14 N 16 O (10 0 0- 00 0 0) P(35) S = 1.66*10 -22 cm 14 N 2 18 O ... (10 0 0- 00 0 0) P(9) S = 2.43*10 -22 cm 14 N 2 16 O (11 1 0-01 1 0) P(56) S = 7.46*10 -23 cm T = 81.2 ... Diapositiva 1 ...

Unbenannt-1

... Unbenannt- 1 Magnitude analysis Due to the small network extension and the unsolidated sediment fill ... bootstrap method (Efron, 1977). Insheim reservoir During day hours (6: 00-20: 00, 56 events) the catalogue of ... Unbenannt- 1 ... Unbenannt- 1 Magnitude analysis Due to the small network extension and the unsolidated sediment fill ... Unbenannt- 1 ...

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... nm Confocal Raman Spectroscopy 2 5 0 2 7 5 3 0 0 3 2 5 3 5 0 3 7 5 4 0 0 4 2 5 # 1 # 2 # 3 E g A 1 g ... E g I n t e n s i t y ( A r b . U n i t s ) W a v e n u m b e r ( c m - 1 ) T 2 g YAG peaks # 1 #2 # 3 ... nm Confocal Raman Spectroscopy 2 5 0 2 7 5 3 0 0 3 2 5 3 5 0 3 7 5 4 0 0 4 2 5 # 1 # 2 # 3 E g A 1 g ... E g I n t e n s i t y ( A r b . U n i t s ) W a v e n u m b e r ( c m - 1 ) T 2 g YAG peaks # 1 #2 # 3 ... Slide 1 ...

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...                                12 22 11 66 2212 1211 12 22 11 00 0 0       Q QQ QQ 1221 1 21 2 21 1 1 2 212 21 11 1/ 1 ... 1 QQQ Q Q Q                   66 2212 1211 00 0 0 Q QQ QQ Q 1122 QQ  121166 ...                                12 22 11 66 2212 1211 12 22 11 00 0 0       Q QQ QQ 1221 1 21 2 21 1 1 2 212 21 11 1/ 1 ... 1 QQQ Q Q Q                   66 2212 1211 00 0 0 Q QQ QQ Q 1122 QQ  121166 ... Slide 1 ...

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... / phase continuous) 82cm- 1 of Mode Hop Free Tuning at 5.2um 0 10 20 30 40 50 60 70 1880 1890 1900 1910 ... acetone scan with 0.5 cm- 1 resolution 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 1210 1220 1230 1240 1250 1260 1270 ... / phase continuous) 82cm- 1 of Mode Hop Free Tuning at 5.2um 0 10 20 30 40 50 60 70 1880 1890 1900 1910 ... acetone scan with 0.5 cm- 1 resolution 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 1210 1220 1230 1240 1250 1260 1270 ... Slide 1 ...

Programm_5_Layout 1

... Conference Helpline 0041 (0)79 770 84 29 W-LAN 1. Check available WLAN’s 2. Connect to WLAN „public“ 3. Open ... Programm_5_Layout 1 for Theoretical Studies PAULI CENTER The Swiss National Science Foundation ETH ... Conference Helpline 0041 (0)79 770 84 29 W-LAN 1. Check available WLAN’s 2. Connect to WLAN „public“ 3. Open ... Programm_5_Layout 1 ... Programm_5_Layout 1 ...

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... the system, while the failure likelihood of the components is given qi = 0.01, i = 1, 2, 3, 4. Q2 ... qj = 0.01, j = 1, 2, 3, 4. ... the system, while the failure likelihood of the components is given qi = 0.01, i = 1, 2, 3, 4. Q2 ... qj = 0.01, j = 1, 2, 3, 4. ... 1 ...

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