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... 1 1 Reliability of Technical Systems Tutorial # 5 (FTA Cont) Due: October 26th, 2010 The cooling ... : 9.999E- 5 Transducer: 5E- 5 Electric Valve: 4.182E- 3 Electric Pump: 7.937E- 3 Power supply: 1E-4 Backup ... 1 1 Reliability of Technical Systems Tutorial # 5 (FTA Cont) Due: October 26th, 2010 The cooling ... : 9.999E- 5 Transducer: 5E- 5 Electric Valve: 4.182E- 3 Electric Pump: 7.937E- 3 Power supply: 1E-4 Backup ... 1 ...
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... a multi-output process, which produces 10 kg of product A and 5 kg of product B per minute. 1 kg of ... product A is worth 20 CHF, 1 kg of B is worth 5 CHF. The process emits 120 kg CO2 per hour. Product B can ... a multi-output process, which produces 10 kg of product A and 5 kg of product B per minute. 1 kg of ... product A is worth 20 CHF, 1 kg of B is worth 5 CHF. The process emits 120 kg CO2 per hour. Product B can ... 1 ...
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... ash on a landfill for stabilized residues: 2 2 260'295.9) 5 2 1(%2000'110 COkg t COkg t ... landfilling the fly ash on a landfill for stabilized residues: t COkg t COkg 22 3.135.9) 5 2 1( total: t ... ash on a landfill for stabilized residues: 2 2 260'295.9) 5 2 1(%2000'110 COkg t COkg t ... landfilling the fly ash on a landfill for stabilized residues: t COkg t COkg 22 3.135.9) 5 2 1( total: t ... 1 ...
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... (flammable, non-flammable and poisonous) Class 3 Flammable liquids Class 4 Flammable solids Class 5 Oxidizing ... 1 www.lsa.ethz.ch/education/vorl Methods of Technical Risk Assessment in a Regional Context Methods ... (flammable, non-flammable and poisonous) Class 3 Flammable liquids Class 4 Flammable solids Class 5 Oxidizing ... 1 ... 1 ...
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... the system, while the failure likelihood of the components is given qi = 0.01, i = 1, 2, 3, 4. Q2 ... qj = 0.01, j = 1, 2, 3, 4. ... the system, while the failure likelihood of the components is given qi = 0.01, i = 1, 2, 3, 4. Q2 ... qj = 0.01, j = 1, 2, 3, 4. ... 1 ...
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... 1 Reliability of Technical Systems Tutorial # 3 Solution 1. Consider the probability density ... = 1/1.28×10−4= 7812.5 hours MTTFs= MTTFc/4=1953.125 hours 3. A space vehicle requires three out four ... 1 Reliability of Technical Systems Tutorial # 3 Solution 1. Consider the probability density ... = 1/1.28×10−4= 7812.5 hours MTTFs= MTTFc/4=1953.125 hours 3. A space vehicle requires three out four ... 1 ...
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... 1 Reliability of Technical Systems Tutorial # 3 Due : October 12, 2010 1. Consider the probability ... component ? 3. A space vehicle requires three out four of its main engines to operate in order to achieve ... 1 Reliability of Technical Systems Tutorial # 3 Due : October 12, 2010 1. Consider the probability ... 1 ... 1 ...
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... [ 1/hour] • Failure rate of the spare tire: 𝜆𝑆= 10- 3 [ 1/hour] • Repair duration (time to install the ... tire (you may assume repair rate is about 6⋅10- 3 ( 1/hour) ). In this case, what is the probability that ... [ 1/hour] • Failure rate of the spare tire: 𝜆𝑆= 10- 3 [ 1/hour] • Repair duration (time to install the ... tire (you may assume repair rate is about 6⋅10- 3 ( 1/hour) ). In this case, what is the probability that ... 1 ...
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... gl037074 1.. 5 How much climate change can be avoided by mitigation? Warren M. Washington, 1 Reto ... Knutti,2 Gerald A. Meehl, 1 Haiyan Teng, 1 Claudia Tebaldi, 3 David Lawrence, 1 Lawrence Buja, 1 and Warren G ... gl037074 1.. 5 ... gl037074 1.. 5 How much climate change can be avoided by mitigation? Warren M. Washington, 1 Reto ... gl037074 1.. 5 ...
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... nl302918d 1.. 5 Exchange Biasing Single Molecule Magnets: Coupling of TbPc2 to Antiferromagnetic ... measured at B = ± 0.05 T, T = 8 K on TbPc2/CoO (10 ML) (top), TbPc2/CoO ( 3 ML) (middle), and TbPc2/CoO ( 5 ... nl302918d 1.. 5 ... nl302918d 1.. 5 Exchange Biasing Single Molecule Magnets: Coupling of TbPc2 to Antiferromagnetic ... nl302918d 1.. 5 ...
