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Network Virtualization and Data Center Networks 263-3825-00 Introduction

... Data Center Networks 263-3825- 00 SDN - Introduction Qin Yin Fall Semester 2013 1 The Road to SDN: An ... Network Virtualization and Data Center Networks 263-3825- 00 Introduction Network Virtualization and ... Data Center Networks 263-3825- 00 SDN - Introduction Qin Yin Fall Semester 2013 1 The Road to SDN: An ... Network Virtualization and Data Center Networks 263-3825- 00 Introduction ... Network Virtualization and Data Center Networks 263-3825- 00 Introduction ...

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...  & Outlook 2 S ou rc e:  w es tu m fa hr un g. ch  (2 00 8) Target 3 fm: Street restructuring ls: Wollishofen ... Slide 1 “Westumfahrung Zurich”: Real  World Study with MATSim May 22, 2008, IVT­Seminar, ETH Zurich ...  & Outlook 2 S ou rc e:  w es tu m fa hr un g. ch  (2 00 8) Target 3 fm: Street restructuring ls: Wollishofen ... Slide 1 ... Slide 1 ...

Microsoft Word - PTS WS99-00.doc

... ) Fridays 4- 5 pm; Room ML K 25 (unless otherwise noted), Sonneggstrasse 3, CH-8092 Zürich September 3 ... Microsoft Word - PTS WS99- 00.doc Eidgenössische Technische Hochschule Zürich Ecole polytechnique ... ) Fridays 4- 5 pm; Room ML K 25 (unless otherwise noted), Sonneggstrasse 3, CH-8092 Zürich September 3 ... Microsoft Word - PTS WS99- 00.doc ... Microsoft Word - PTS WS99- 00.doc ...

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... Slide 1 10/ 5/2015 1 1 Lecture # 3 – Fall 2015 1 D. Mohr 151-0735: Dynamic behavior of materials and ... hence - 1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 0 1 2 3  l 10/ 5/2015 25 25 Lecture # 3 – Fall 2015 25 D ... Slide 1 10/ 5/2015 1 1 Lecture # 3 – Fall 2015 1 D. Mohr 151-0735: Dynamic behavior of materials and ... hence - 1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1 0 1 2 3  l 10/ 5/2015 25 25 Lecture # 3 – Fall 2015 25 D ... Slide 1 ...

Slide 1

... Materials, Polymer Chemistry, ETH Zürich Short fiber composites ‰ Polymers have a stiffness of 1- 3 GPa ... , p2, p3) ‰ System with N fibers – 2nd order orientation tensor – 4th & 6th order tensors 1 φ θ p 2 3 ... Materials, Polymer Chemistry, ETH Zürich Short fiber composites ‰ Polymers have a stiffness of 1- 3 GPa ... , p2, p3) ‰ System with N fibers – 2nd order orientation tensor – 4th & 6th order tensors 1 φ θ p 2 3 ... Slide 1 ...

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... = {0 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔✔ Sweep3D ✖ MILC ✔ HOMME ✔ XNS ... () } Instrumentation Performance measurements (profiles) Input Output 1. foo 2. compute 3. main 4. bar […] Ranking: 1 ... = {0 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔✔ Sweep3D ✖ MILC ✔ HOMME ✔ XNS ... () } Instrumentation Performance measurements (profiles) Input Output 1. foo 2. compute 3. main 4. bar […] Ranking: 1 ... Slide 1 ...

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... 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔ ✔ Sweep3D ✖ MILC ✔ HOMME ✔ XNS ... ) Input Output 1. foo 2. compute 3. main 4. bar […] Ranking: 1. Asymptotic 2. Target scale pt p1 = 128 p2 ... 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔ ✔ Sweep3D ✖ MILC ✔ HOMME ✔ XNS ... ) Input Output 1. foo 2. compute 3. main 4. bar […] Ranking: 1. Asymptotic 2. Target scale pt p1 = 128 p2 ... Slide 1 ...

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... spcl.inf.ethz.ch @spcl_eth 16 I = {0 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔ ✔ Sweep3D ✖ MILC ... () bar() compute() } Instrumentation Performance measurements (profiles) Input Output 1. foo 2. compute 3 ... spcl.inf.ethz.ch @spcl_eth 16 I = {0 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔ ✔ Sweep3D ✖ MILC ... () bar() compute() } Instrumentation Performance measurements (profiles) Input Output 1. foo 2. compute 3 ... Slide 1 ...

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... 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔ ✔ Sweep3D ✖ MILC ✔ HOMME ✔ XNS ... ) Input Output 1. foo 2. compute 3. main 4. bar […] Ranking: 1. Asymptotic 2. Target scale pt p1 = 128 p2 ... 2 , 1 2 , 2 2 , 3 2 , 4 2 , 5 2 , 6 2 } J = {0,1,2} n = 5 ✔ ✔ Sweep3D ✖ MILC ✔ HOMME ✔ XNS ... ) Input Output 1. foo 2. compute 3. main 4. bar […] Ranking: 1. Asymptotic 2. Target scale pt p1 = 128 p2 ... Slide 1 ...

Diapositiva 1

... -TONES MODULATION RESULTS 0 1 2 3 4 15 N 14 N 16 O (10 0 0- 00 0 0) P(35) S = 1.66*10 -22 cm 14 N 2 18 O ... (10 0 0- 00 0 0) P(9) S = 2.43*10 -22 cm 14 N 2 16 O (11 1 0-01 1 0) P(56) S = 7.46*10 -23 cm T = 81.2 ... -TONES MODULATION RESULTS 0 1 2 3 4 15 N 14 N 16 O (10 0 0- 00 0 0) P(35) S = 1.66*10 -22 cm 14 N 2 18 O ... (10 0 0- 00 0 0) P(9) S = 2.43*10 -22 cm 14 N 2 16 O (11 1 0-01 1 0) P(56) S = 7.46*10 -23 cm T = 81.2 ... Diapositiva 1 ...

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