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... = 1/1.28× 10−4= 7812.5 hours MTTFs= MTTFc/4=1953.125 hours 3. A space vehicle requires three out four ... = 100 (hrs) and Rs ( 100) = 0.95 Solve the equation above and λc=1.28× 10−4 ( 1/hour), which means that the ... = 1/1.28× 10−4= 7812.5 hours MTTFs= MTTFc/4=1953.125 hours 3. A space vehicle requires three out four ... = 100 (hrs) and Rs ( 100) = 0.95 Solve the equation above and λc=1.28× 10−4 ( 1/hour), which means that the ... 1 ...

1

... . 38 Abs. 1 fest- gelegten Minima erreichen. 3 Für das Master-Diplom werden maximal 100 KP angerechnet ... : Schlussbestimmungen 42 – 44 Anhang Ausgabe: 16.11.2010 – 3 1 Federführendes Departement 2 Mit Änderungen gemäss ... . 38 Abs. 1 fest- gelegten Minima erreichen. 3 Für das Master-Diplom werden maximal 100 KP angerechnet ... : Schlussbestimmungen 42 – 44 Anhang Ausgabe: 16.11.2010 – 3 1 Federführendes Departement 2 Mit Änderungen gemäss ... 1 ...

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